6.3=14t+0.59.8t^2

Solution for 6.3=14t+0.59.8t^2 equation:

6.3=14t+0.59.8t^2

We move all terms to the left:

6.3-(14t+0.59.8t^2)=0

We get rid of parentheses

-0.59.8t^2-14t+6.3=0

We add all the numbers together, and all the variables

-0.472t^2-14t+6.3=0

a = -0.472; b = -14; c = +6.3;
Δ = b2-4ac
Δ = -142-4·(-0.472)·6.3
Δ = 207.8944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-\sqrt{207.8944}}{2*-0.472}=\frac{14-\sqrt{207.8944}}{-0.944}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+\sqrt{207.8944}}{2*-0.472}=\frac{14+\sqrt{207.8944}}{-0.944}
$